Therefore , P (an ace or a king in the second draw)

= P (ace in first draw) . P (ace or king in the second draw)

=

(2) P (A) = , if the first card is a king.

Now in the remaining lot of 51 cards, there are now 4 aces and 3 kings.

Therefore, P₂ (an ace or a king in the second draw)

= P (a king in the first draw) . P (ace or king in the second draw)

=

(3) If the first draw shows neither an ace nor a king,

[Note 52 - (4 kings + 4 aces) ] = 44.

There are now 4 aces and 4 kings left in 52 cards

Therefore P₃ (ace or king in the second draw)

= P (Neither an ace nor a king) ´ P(ace or king in the second draw).

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Index

7. 1 Introduction
7.2 Trial
7.3 Sample Space
7. 4 Definition of Probability
7. 5 The Laws of Probability
7. 6 Conditional Probability
7. 7 Theoretical Distribution
7. 8 Binomial Distribution
7. 9 Normal Distribution
Chapter 8