Example 1
Areas of two similar triangles are 144 sq.cm. and 81 sq.cm. If one side of the first triangle is 6 cm then find the corresponding side of the second triangle.
Solution :
= 4.5 c.m.
Example 2
The side of an equilateral triangle ABC is 5 cm.
Find the length of the side of another equilateral D
PQR whose area is four times area of D
ABC.
Solution:
Since both triangles are equilateral they are similar.
Example 3
The corresponding sides of two similar triangles are 4 cm and 6 cm. Find the ratio of the areas of the triangles.
Solution:
Example 4
D ABC ~ D PQR such that l (seg.AB) : l (seg.PQ) that is 8 : 6. If area of D ABC is 48 sq.cm what is the area of the smaller triangle.
Solution:
Example 5
In a trapezium ABCD, side AB çç CD. The diagonals AC and BD cut each other at M.
Prove that 
Solution: 
To Prove that
Consider
D
AMB and D CMD.
Ð
AMB @
Ð CMD, vertical angles
Ð
BAM @
Ð DCM alternate angles
\ By AA test
D
AMB ~ D
CMD \
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