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              Let’s use the Kb and Kf chart and the above 
              formulae to solve the following problems. 
Example 
What will be the freezing point and boiling point of a solution containing 3.8 gms of benzoic acid in 50 gms of chloroform ? 
  
            Freezing point depression 
              
            D Tf	= 0.623 ´ 4.68 = 
              2.915 
So, the freezing point of chloroform solution 
- 63.5  -  2.91	=   - 66.4150C 
Boiling point elevation 
             
            D Tb	= 0.623 ´ 3.63 	= 
              2.261  
So, the boiling point of chloroform solution 
61.2  +  2.261 	=  63.460C 
Example  
What will be the molecular weight of the solute if a solution prepared from 500 gms of a solute in 3 kg of water has a boiling point elevation f 20C than that of pure water ? 
  
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