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Let’s use the Kb and Kf chart and the above formulae to solve the following problems.

Example

What will be the freezing point and boiling point of a solution containing 3.8 gms of benzoic acid in 50 gms of chloroform ?

Freezing point depression

D Tf = 0.623 ´ 4.68 = 2.915

So, the freezing point of chloroform solution

- 63.5 - 2.91 = - 66.4150C

Boiling point elevation

D Tb = 0.623 ´ 3.63 = 2.261

So, the boiling point of chloroform solution

61.2 + 2.261 = 63.460C

Example

What will be the molecular weight of the solute if a solution prepared from 500 gms of a solute in 3 kg of water has a boiling point elevation f 20C than that of pure water ?

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[next chapter]

Index

8.1 Nature of Solution
8.2 Heat of Solutions
8.3 Concentration of Solution
8.4 Effect of Temperature and Pressure on Solubility
8.5 Boiling Point and Freezing Point of Solution

Chapter 9





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