1. From a ship, port A is 43.6 nautical miles away on a course of 306⁰ , while port B is on a course of 163⁰ . If the ports are 87.5 nautical miles apart, how far is the ship from the port B ?

Let 'C' denotes ship. From the fig.

Then Ð C = 306⁰ - 163⁰ = 143⁰

2. In running a line PQ, S 38⁰ 42' E from P, a surveyor encounter a swamp. At A on the line and one edge of the swamp, he changes his direction to N 61⁰ E for a distance of 1500 ft. to B. He then sights to other edge of the swamp, the direction being S 10⁰ 31' W. If this line meets PQ in C, find the distance from B to C, the angle through which he must turn from BC to continue on the original line and distance AC across the swamp.

Solution

Index

3. 1 Solving Right Triangles
3. 2 Law of Cosines
3. 3 Law of Sines
3. 4 The Ambiguous Case of Law of Sines
3. 5 Areas of Triangles
Supplementary Problems

Chapter 4