Example 1
Solve the triangle ABC, b = 472.12, c = 607.44, A = 1250
15'
Solution
Using Law of cosines, a2 = b2 + c2
- 2bc cos A we get
\ a2 = (472.12)2
+ (607.44)2 - 2 (472.12) (607.44) cos (1250
15')
\ a2 = 922829.21
\ a = 960.64
Using Law of sines to find smaller angle from remaining two
Example 2
The legs of an isosceles triangle are 28 each. They include an
angle of 170 . Solve the triangle.
Solution
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