Example A purse contains 6 silver coins
and 3 copper coins. Another purse contains 4 silver coins and 5
copper coins. A purse is selected at random and a coin is drawn
from it. What is the probability that it is a silver coin?
Solution :
Let A = the first purse selected
B = the second purse is selected
C = a silver coin is drawn from the purse
Since there are two purses
P (A) =
and P (B) =
Suppose the event A has occurred. Since
there are 6 silver coins out of 9
P (C/A) =
The probability of getting the first purse and a silver coin from it is
P (A Ç
C) = P (A) . P (C/ A) =
Similarly, suppose B has occurred then P (C/B) =
P ( B Ç C) = P (B) P
(C/ B) =
Now A Ç
C and B Ç C are mutually
exclusive.
P (A Ç
C È
B Ç
C) = P (A Ç
C) + P (B Ç C) =
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