Example Calculate ‘ R ’ of 6 students from the following data.
Marks in Stats :
|
40
|
42
|
45
|
35
|
36
|
39
|
Marks in English :
|
46
|
43
|
44
|
39
|
40
|
43
|
Solution:
Marks in Stats
|
R1
|
Marks in English
|
R2
|
R1 - R2
|
(R1 -R2)2
=D2
|
40
|
3
|
46
|
1
|
2
|
4
|
42
|
2
|
43
|
3.5
|
-1.5
|
2.25
|
45
|
1
|
44
|
2
|
-1
|
1
|
35
|
6
|
39
|
6
|
0
|
0
|
36
|
5
|
40
|
5
|
0
|
0
|
39
|
4
|
43
|
3.5
|
0.5
|
0.25
|
|
|
|
|
|
|
N = 6
|
|
|
|
S D = 0
|
S D2 = 7.50
|
Here m = 2 since in series of marks in English of items of values 43 repeated twice.
Example The value of Spearman’s rank correlation coefficient for a certain number of pairs of observations was found to be 2/3. The sum of the squares of difference between the corresponding rnks was 55. Find the number of pairs.
Solution: We have
|