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Let the length of the semi-diagonals of the rhombus be 3x and 4x respectively.
The semi diagonals and the side form a right angled triangle.
(4x)2 + (3x)2 = (10)2
25x2 = 100
x2 = 4
x = 2
The length of the diagonals is 16 and 12 respectively.
Area of a rhombus = 
= 96
Ans : B
Add the remainders and divide the sum by the common divisor i.e. 3.
We get which gives no remainder.
Ans : C
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