1. wt ¹ 0

   w⁴ t⁴ = w⁴ t⁴

   = (-w² t² )²

   Ans : C

2. The number of candies in the bag is not given.
   Therefore the relationship cannot be determined.

   Ans : D

3. Quadrilateral XYOW is not a cyclic quadrilateral since vertex 'O' is the center of the circle. Hence the relationship cannot be determined.

   Ans : D

4. If any number between 0 and 1 is squared it can never exceed 1.
   y² < 1

   Ans : B

5. Let P be an intersection point of LM and HK.
   Consider D KPM,
   \ m Ð KPM + k + m = 180 ......(1) [Sum of the measures of angles of a triangle]

   Similarly, D LPH,
   m Ð LPH + h + l = 180 ......(2) [Sum of the measures of angles of a triangle]

   From (1) and (2),
   m Ð KPM + k + m = m Ð LPH + h + l
   But Ð KPM @ Ð LPH [Vertically opposite angles]
   \ m Ð KPM = m Ð LPH

   Using the cancellation property of equality, we get
   k + m = h + l

   Ans : C

6. Area of the parallelogram JKLM will be less than 12 because mÐ JML is less than 90.
   12 > Area of parallelogram.

   Ans : A

7. Assuming the least positive value of b i.e. b = 1
   The given expression
   

   [next page]

Index

PART IV

Drill :

Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Answer Explanation To The Drill
Section 1 : Verbal Reasoning
Section 2 : Mathematical Reasoning
Section 3 : Verbal Reasoning
Section 4 : Mathematical Reasoning
Section 5 : Reading Comprehension
Section 6 : Mathematical Reasoning
Section 7 : Verbal Reasoning

Test 1