2) | x | < a is equal to - a < x < a
3) | x | < a is equal to x < - a or x > a
using (3) we have 2x + 3 < - 3 or 2x + 3 > 3
4 4
solving, 2x + 3 < - 12 or 2x + 3 > 12
2x + 3 - 3 < -12 - 3 or 2x + 3 - 3 > 12 - 3
Þ 2x < - 15 or 2x > 9
Þ x < - 15/2 or x > 9/2
The solution set is { x | x < - 7.5 or x > 4.5 }
OR (- ¥ , -7. 5) È (4.5, ¥ )
Graphically
|