13. C
    If V & W stand on O’s shoulders and M stands on the same level as N and P and is the only acrobat between them it presupposes two things (i) O is on the second level in the center Q will be on the extreme side. Also (ii) since Q is not standing, he must have fallen. Therefore if Q falls, exactly three of the child acrobat’s must fall.

    

14. C
    Since W stands on the shoulders of N and P, it naturally follows that W is on the second level. Also since X stands on the shoulders of M and V, M and V must be on the second level which is a corollary of the condition child acrobats cannot be in the first level. (That leaves only one acrobat on the second level). Thus on the second level VMW will stand.

    

    Answers for 15 -20

    A four-by-four grid listing prizes, breeds, owners, and dog names will be needed. Using the information given and the process of elimination, you can come up with the following chart :

    

15. A
    Once statement (7) identifies the 4th prizes winner and you determine that Mr. Grossman’s dog therefore won 3rd prize, it follows that, since Max won 2nd prize, Ms. Huntley’s Kelly was the Collie that won first prize.

16. D
    The same reasoning process used in question 15 makes Mr. Grossman’s dog the Airedale that won third prize.

     

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Index

Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section
Answer key to Test 4

PART I To The Students