13. D ADE is isosceles ( given )

\ x = 30⁰

\ exterior angle = 30 + 30 = 60⁰

Also D ADC is isosceles (given )

\ Ð ACD = y⁰

\ y + y + 60 = 180⁰ ( angles of D ADC )

\ y = 60⁰

\ D ADC is equilateral

\ AC = DC

But DC + ED ( given )

\ AC = ED

Hence C.

14. From ( 13 ) above w = 60⁰

    Also in D ABC, z = 60⁰

    Since AC = DE = AB = BC

    i.e. since D ABC is also equilateral

    \ w = z

    Hence C.

15. From ( 13 ) x = 30⁰ and y = 60⁰

    \ x + y = 90⁰

    Hence C.

     

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Index

Test 4
Section 1 : Verbal Section
Section 2 : Quantitative Section
Section 3 : Analytical Section
Section 4 : Quantitative Section
Section 5 : Verbal Section
Section 6 : Analytical Section
Section 7 : Analytical Section
Answer key to Test 4

PART I To The Students