Questions 10 & 11 refer to this diagram
-
In quadrant III 'a' and 'b' are both negative. Hence a ³ b or a < b.
Hence D.
In quadrant IV c is positive and d is negative.
Hence A.
Area of square with side 16
= ( side )2
= 162
= 256 |
Area of circle with
diameter 18,
i.e. radius 9
= p r2
= p ´ 92 = 81 p
= 81 ´ 3.142 » 254.502 |
Hence A.
122 + 132 + 142 3 ´ ( 13 )2
122 + + 142 132 + + 132
Canceling 132 from each side
144 + 196 338
Alex is heavier than Bill who is heavier than Clyde, also Dick is heavier than Clyde. Since Alex and Dick are both heavier than Clyde, it is not possible to compare Alex’s weight and Dick’s weight.
Hence D.
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Index
Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section
Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section Section 7 : Quantitative Section Answer key to Test 3
Answer Explanation To Test 3
Section 1 : Verbal
Section
Section 2 : Quantitative
Section Section 3 : Analytical
Section
Section 4 : Quantitative
Section
Section 5 : Verbal
Section
Section 6 : Analytical
Section
Section 7 : Quantitative
Section
Test 4
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